Kryptos K3 Gimlet Trick

I call this the K3 Gimlet Trick, and I believe this is the method Ed Scheidt intended.

Qs are wild and the italicized definitions are paraphrased from Merriam Webster.

Put K3 in monospace with row lengths as they are in the sculpture, and no ?. Identify GIMLET - to pierce - at the top of column 24.

ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIA
CHTNREYULDSLLSLLNOHSNOSMRWXMNE
TPRNGATIHNRARPESLNNELEBLPIIACAE
WMTWNDITEENRAHCTENEUDRETNHAEOE
TFOLSEDTIWENHAEIOYTEYQHEENCTAYCR
EIFTBRSPAMHHEWENATAMATEGYEERLB
TEEFOASFIOTUETUAEOTOARMAEERTNRTI
BSEDDNIAAHTTMSTEWPIEROAGRIEWFEB
AECTDDHILCEIHSITEGOEAOSDDRYDLORIT
RKLMLEHAGTDHARDPNEOHMGFMFEUHE
ECDMRIPFEIMEHNLSSTTRTVDOHW

Reduce the column width to 24. Identify LITANY EAST - a sizable set... to the right - at the top of the last column.

ENDYAHROHNLSRHEOCPTEOIBI
DYSHNAIACHTNREYULDSLLSLL
NOHSNOSMRWXMNETPRNGATIHN
RARPESLNNELEBLPIIACAEWMT
WNDITEENRAHCTENEUDRETNHA
EOETFOLSEDTIWENHAEIOYTEY
QHEENCTAYCREIFTBRSPAMHHE
WENATAMATEGYEERLBTEEFOAS
FIOTUETUAEOTOARMAEERTNRT
IBSEDDNIAAHTTMSTEWPIEROA
GRIEWFEBAECTDDHILCEIHSIT
EGOEAOSDDRYDLORITRKLMLEH
AGTDHARDPNEOHMGFMFEUHEEC
DMRIPFEIMEHNLSSTTRTVDOHW

Rotate 90 degrees to the right. Identify WHENCE - out of which place - at the top of column 8.

DAEGIFWQEWRNDE
MGGRBIEHONAOYN
RTOISONEEDRHSD
IDEEETAETIPSHY
PHAWDUTNFTENNA
FAOFDEACOESOAH
ERSENTMTLELSIR
IDDBIUAASNNMAO
MPDAAATYERNRCH
ENREAEECDAEWHN
HEYCHOGRTHLXTL
NODTTTYEICEMNS
LHLDTOEIWTBNRR
SMODMAEFEELEEH
SGRHSRRTNNPTYE
TFIITMLBHEIPUO
TMTLEABRAUIRLC
RFRCWETSEDANDP
TEKEPEEPIRCGST
VULIIREAOEAALE
DHMHETFMYTETLO
OELSRNOHTNWISI
HEEIORAHEHMHLB
WCHTATSEYATNLI

Reduce column width to 8. Identify HINGE - to swing - at the top of the last column.

DAEGIFWQ
EWRNDEMG
GRBIEHON
AOYNRTOI
SONEEDRH
SDIDEEET
AETIPSHY
PHAWDUTN
FTENNAFA
OFDEACOE
SOAHERSE
NTMTLELS
IRIDDBIU
AASNNMAO
MPDAAATY
ERNRCHEN
REAEECDA
EWHNHEYC
HOGRTHLX
TLNODTTT
YEICEMNS
LHLDTOEI
WTBNRRSM
ODMAEFEE
LEEHSGRH
SRRTNNPT
YETFIITM
LBHEIPUO
TMTLEABR
AUIRLCRF
RCWETSED
ANDPTEKE
PEEPIRCG
STVULIIR
EAOEAALE
DHMHETFM
YTETLOOE
LSRNOHTN
WISIHEEI
ORAHEHMH
LBWCHTAT
SEYATNLI

Rotate 90 degrees to the right.

SLOWLYDESPARATLYSLOWLYTHEREMAINSOFPASSAGED
EBRISTHATENCUMBEREDTHELOWERPARTOFTHEDOORWA
TWASREMOVEDWITHTREMBLINGHANDSIMADEATINYBRE
ACHINTHEUPPERLEFTHANDCORNERANDTHENWIDENING
THEHOLEALITTLEIINSERTEDTHECANDLEANDPEEREDI
NTHEHOTAIRESCAPINGFROMTHECHAMBERCAUSEDTHEF
LAMETOFLICKERBUTPRESENTLYDETAILSOFTHEROOMW
ITHINEMERGEDFROMTHEMISTXCANYOUSEEANYTHINGQ

I call this solution K3 THINGS, and another solution - K3 WONDERFUL - also exists.

K3 THINGS was first solved by Denny McDaniels at the NSA; David Stein at the CIA; and civilian Jim Gillogly, all independent of each other.

-Zackery Belanger
Released 30 January 2025

Kryptos Structure: The Tomb of Tutankhamun

A PDF of this image is available here.

-Zackery Belanger
Released 21 September 2024

GRASP Cipher

The following describes a many-layer pen-and-paper cipher type that I believe Ed Scheidt developed for Kryptos. If you’ve seen this system before, please let me know. I've named it the GRASP cipher and created a challenge cipher to demonstrate how it works.

The method allows a key word to be expressed in the ciphertext at each layer, which provides a built-in clue for the next step and allows the codemaker to use as many layers as they like. This method demonstrates that it is at least feasible that sequences like KCAR in Kryptos are meaningful and intentional.

The following GRASP cipher challenge has six layers and is designed to be solved manually:

KXKPXWFTSH?OWPXOVUSUAQBKJQRPGQ

I'll share some important information and how Layers 1 and 2 work, and leave the remaining layers to the interested codebreakers.

[Update: this cipher has been solved by Megan Stewart of Flint, Michigan. Her solution will be made available soon, but I encourage anyone interested to work through the steps on their own.]

Important information:

  1. The 27-letter alphabet for this cipher is: OCGXRJLINSHVBTDQAPZK?WEFYUM

  2. The primary key is Longfellow's translation of Dante's Divine Comedy Vol II: Purgatorio; 1870; by Fields, Osgood & Co, Boston. This edition and printing is required, and only the poem is in play (pages 1 - 166). I've made a searchable PDF with all extraneous content removed available here. The cipher would work even with only the print book in hand, but would take a lot more time to solve.

  3. For built-in clue identification, Q and X are wild.

  4. A word unscrambler is helpful; this one accepts wild characters.

  5. The Layer 1 clue is five characters long, and the remaining clues are all four characters long.

  6. Progress always moves forward in Purgatorio for this implementation, never backward.

  7. All clues occur at the end of the ciphertext.

Layer 1:

KXKPXWFTSH?OWPXOVUSUAQBKJQRPGQ

Inspect the last five characters of the ciphertext, and remember Q and X are wild. These characters can be unscrambled to make four words that occur in Purgatorio: PURGE (p 1, 3, 22, 128, 138), GRASP (p 2, 24), GRAPE (p 16), and GROUP (p 145).

Try the first occurrence of GRASP, which is on page 2. Take the final 30 characters from the page, and transform the ciphertext by summing characters using the given alphabet (e.g. K=20 and V=12, so K+V=32 which is 5, or R):

KXKPXWFTSH?OWPXOVUSUAQBKJQRPGQ
VERENTHEMADEINMEMYKNEESANDBROW
RMYTBNISSONFGMXFVFGIBVESDXPEXH

The last four characters of the new ciphertext contain the scrambled clue for Layer 2.

Layer 2:

Words that can be made from PEXH that occur in Purgatorio are HOPE (p 12, 15, 16, 26, 39, 65, 84, 93, 101, 152) and HELP (p 51). Neither HOPE p 12 nor p 15 yield anything interesting. The third HOPE is works, page 16. Again grab the last 30 characters on the page and transform:

RMYTBNISSONFGMXFVFGIBVESDXPEXH
MASTERSAIDIWHATWAYSHALLWETAKE?
RAIONTPMPQAZTAPZCWBZGZGRHPIQMR

Inspect the last four characters and carry on.

If you are curious, you can try using PURGE, GRAPE, GROUP, and the later occurrence of GRASP in layer 1, and you'll find that none of them lead anywhere. You can also try with four- or six-letter clues if you like; you also won't get anywhere.

In this system false leads occur by chance, but when you're off-path it will usually quickly, always eventually, fall apart.

A carefully chosen alphabet is required for this method. The wild characters need to show up often enough to be useful but not so often as to cause the possible clues to explode in number. How the characters combine to other characters is a delicate balance.

The appearance of a new clue in every layer may make very deep systems possible, especially with a more refined alphabet, additional careful rule relaxations (e.g. V and U could be interchangeable), a mixing in other cipher types (e.g. a careful transposition would re-seed the last four characters), and of course, more books.

-Zackery Belanger
Released 01 September 2024